What are the solutions to the equation x^2-4x+87=0 ?

The solutions to the equation x^2-4x+87=0 are x=2+sqrt(83)i,x=2-sqrt(83)i

Find the zeros of x^2-4x+87=0

The zeros of x^2-4x+87=0 are x=2+sqrt(83)i,x=2-sqrt(83)i

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x^{2} - 4 x + 87 = 0

x = 2 + 83 i, x = 2 - 83 i

Solution steps

x^{2} - 4 x + 87 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 87}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 87 : 283 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 83 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 83 i}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 83 i}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 83 i}{2 \cdot 1} : 2 + 83 i

x = \frac{- ( - 4 ) - 2 83 i}{2 \cdot 1} : 2 - 83 i

The solutions to the quadratic equation are:

x = 2 + 83 i, x = 2 - 83 i

0.25 = - 0.0002 x^{2} + 0.0031 x + 0.9942

4 x^{2} + 6 x = 9 x^{2} - 15 x

3 \cdot a^{2} = 1

5 n + 28 = n^{2}

3 x^{2} + 10 x = - 9

What are the solutions to the equation x^2-4x+87=0 ?
The solutions to the equation x^2-4x+87=0 are x=2+sqrt(83)i,x=2-sqrt(83)i
Find the zeros of x^2-4x+87=0
The zeros of x^2-4x+87=0 are x=2+sqrt(83)i,x=2-sqrt(83)i