What are the solutions to the equation (t)=-0.0002t^2+0.06t,0<= x<= 240 ?

The solutions to the equation (t)=-0.0002t^2+0.06t,0<= x<= 240 are t=-(1.88)/(0.0004),t=0

Find the zeros of (t)=-0.0002t^2+0.06t,0<= x<= 240

The zeros of (t)=-0.0002t^2+0.06t,0<= x<= 240 are t=-(1.88)/(0.0004),t=0

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The solutions to the equation (t)=-0.0002t^2+0.06t,0<= x<= 240 are t=-(1.88)/(0.0004),t=0

The zeros of (t)=-0.0002t^2+0.06t,0<= x<= 240 are t=-(1.88)/(0.0004),t=0

(t) = - 0.0002 t^{2} + 0.06 t, 0 \leq x \leq 240

t = - \frac{1.88}{0.0004}, t = 0

Decimal Notation

t = - 4700, t = 0

Solution steps

(t) = - 0.0002 t^{2} + 0.06 t

Refine

t = - 0.0002 t^{2} + 0.06 t

Switch sides

- 0.0002 t^{2} + 0.06 t = t

Move

t

to the left side

- 0.0002 t^{2} - 0.94 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 0.94 ) \pm ( - 0.94 ) ^{2} - 4 ( - 0.0002 ) \cdot 0}{2 ( - 0.0002 )}

(- 0.94)^{2} - 4 (- 0.0002) \cdot 0 = 0.94

t_{1, 2} = \frac{- ( - 0.94 ) \pm 0.94}{2 ( - 0.0002 )}

Separate the solutions

t_{1} = \frac{- ( - 0.94 ) + 0.94}{2 ( - 0.0002 )}, t_{2} = \frac{- ( - 0.94 ) - 0.94}{2 ( - 0.0002 )}

t = \frac{- ( - 0.94 ) + 0.94}{2 ( - 0.0002 )} : - \frac{1.88}{0.0004}

t = \frac{- ( - 0.94 ) - 0.94}{2 ( - 0.0002 )} : 0

The solutions to the quadratic equation are:

t = - \frac{1.88}{0.0004}, t = 0

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(x + 3) (x - 2) = 2 x^{2} - 18

2 - 4 x + x^{2} = 0

- 2 x^{2} - 4 x + 2 = 0

0 = x^{2} + 3 x + 6

What are the solutions to the equation (t)=-0.0002t^2+0.06t,0<= x<= 240 ?
The solutions to the equation (t)=-0.0002t^2+0.06t,0<= x<= 240 are t=-(1.88)/(0.0004),t=0
Find the zeros of (t)=-0.0002t^2+0.06t,0<= x<= 240
The zeros of (t)=-0.0002t^2+0.06t,0<= x<= 240 are t=-(1.88)/(0.0004),t=0