What is factor n^2-3n-18 ?

The solution to factor n^2-3n-18 is (n+3)(n-6)

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factor n^2-3n-18

factor

n^{2} - 3 n - 18

(n + 3) (n - 6)

Solution steps

n^{2} - 3 n - 18

Break the expression into groups

= (n^{2} + 3 n) + (- 6 n - 18)

Factor out

n

from

n^{2} + 3 n : n (n + 3)

Factor out

- 6

from

- 6 n - 18 : - 6 (n + 3)

= n (n + 3) - 6 (n + 3)

Factor out common term

n + 3

= (n + 3) (n - 6)

4 - \frac{10 u}{9} < 12

(x - 5)^{2} - 2

c^{4} - 2 c^{2} + c^{3} - 2 c

\frac{x - 2}{x + 3} > 0

\frac{1}{5} (1 + \frac{3}{5} - \frac{9}{10}) + [2 + 5 (\frac{2}{9} - 3)]