What is 1/5 (1+3/5-9/10)+[2+5(2/9-3)] ?

The solution to 1/5 (1+3/5-9/10)+[2+5(2/9-3)] is -5287/450

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1/5 (1+3/5-9/10)+[2+5(2/9-3)]

\frac{1}{5} (1 + \frac{3}{5} - \frac{9}{10}) + [2 + 5 (\frac{2}{9} - 3)]

- \frac{5287}{450}

Solution steps

\frac{1}{5} (1 + \frac{3}{5} - \frac{9}{10}) + [2 + 5 (\frac{2}{9} - 3)]

Follow the PEMDAS order of operations

Calculate within parentheses

(1 + \frac{3}{5} - \frac{9}{10}) : \frac{7}{10}

= \frac{1}{5} \cdot \frac{7}{10} + [2 + 5 (\frac{2}{9} - 3)]

Calculate within parentheses

[2 + 5 (\frac{2}{9} - 3)] : - \frac{107}{9}

= \frac{1}{5} \cdot \frac{7}{10} - \frac{107}{9}

Multiply and divide (left to right)

\frac{1}{5} \cdot \frac{7}{10} : \frac{7}{50}

= \frac{7}{50} - \frac{107}{9}

Add and subtract (left to right)

\frac{7}{50} - \frac{107}{9} : - \frac{5287}{450}

= - \frac{5287}{450}

48

r^{2} + 9 r + 14 = 0

2 x^{2} + 25 = 13 x

5 y^{2} - 21 y + 18

\frac{m + 7}{m ^{2} + 4 m - 21}

What is 1/5 (1+3/5-9/10)+[2+5(2/9-3)] ?
The solution to 1/5 (1+3/5-9/10)+[2+5(2/9-3)] is -5287/450