What are the solutions to the equation 4x^2+3x=-3x ?

The solutions to the equation 4x^2+3x=-3x are x=0,x=-3/2

Find the zeros of 4x^2+3x=-3x

The zeros of 4x^2+3x=-3x are x=0,x=-3/2

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4 x^{2} + 3 x = - 3 x

x = 0, x = - \frac{3}{2}

Decimal Notation

x = 0, x = - 1.5

Solution steps

4 x^{2} + 3 x = - 3 x

Move

3 x

to the left side

4 x^{2} + 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

6^{2} - 4 \cdot 4 \cdot 0 = 6

x_{1, 2} = \frac{- 6 \pm 6}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 6 + 6}{2 \cdot 4}, x_{2} = \frac{- 6 - 6}{2 \cdot 4}

x = \frac{- 6 + 6}{2 \cdot 4} : 0

x = \frac{- 6 - 6}{2 \cdot 4} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 0, x = - \frac{3}{2}

y^{2} + 17 y + 16 = 0

x^{2} + 2 x + 50

\frac{6 ^{2}}{1 5 ^{2}} + \frac{x ^{2}}{1 0 ^{2}} = 1

104.607075 = 0.1775 x^{2} - 36.621 x + 2005.1

7 r^{2} + 9 = - 81

What are the solutions to the equation 4x^2+3x=-3x ?
The solutions to the equation 4x^2+3x=-3x are x=0,x=-3/2
Find the zeros of 4x^2+3x=-3x
The zeros of 4x^2+3x=-3x are x=0,x=-3/2