What are the solutions to the equation b^2=2 ?

The solutions to the equation b^2=2 are b=sqrt(2),b=-sqrt(2)

Find the zeros of b^2=2

The zeros of b^2=2 are b=sqrt(2),b=-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

b^{2} = 2

b = 2, b = - 2

Decimal Notation

b = 1.41421 \dots, b = - 1.41421 \dots

Solution steps

b^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 2, b = - 2

a x^{2} + b x + 7 = k (3 x^{2} - 2 x + 1)

4 x^{2} + 20 x + 25 = 121

((3 x)^{2} + (4 x)^{2}) - 4 x + 975 x = 5 x^{2}

x^{2} - 2 (k - 1) x + 6 k - 11 = 0

a^{2} + 2 1^{2} = 2 9^{2}

What are the solutions to the equation b^2=2 ?
The solutions to the equation b^2=2 are b=sqrt(2),b=-sqrt(2)
Find the zeros of b^2=2
The zeros of b^2=2 are b=sqrt(2),b=-sqrt(2)