What are the solutions to the equation -2y^2+4R^2=0 ?

The solutions to the equation -2y^2+4R^2=0 are y=Rsqrt(2),y=-Rsqrt(2)

Find the zeros of -2y^2+4R^2=0

The zeros of -2y^2+4R^2=0 are y=Rsqrt(2),y=-Rsqrt(2)

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- 2 y^{2} + 4 R^{2} = 0

y = R 2, y = - R 2

Solution steps

- 2 y^{2} + 4 R^{2} = 0

Move

4 R^{2}

to the right side

- 2 y^{2} = - 4 R^{2}

Divide both sides by

- 2

y^{2} = 2 R^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 2 R^{2}, y = - 2 R^{2}

Simplify

2 R^{2} : R 2

Simplify

- 2 R^{2} : - R 2

y = R 2, y = - R 2

y^{2} - 300 y + 10000 = 0

(2 - x) \cdot (- 2 - x) + 1 = 0

y, m^{2} \cdot 3 y - mλ = y^{2}

r, z = 4 - r^{2}

0.5 q^{2} + 30 q - 350 = 0

What are the solutions to the equation -2y^2+4R^2=0 ?
The solutions to the equation -2y^2+4R^2=0 are y=Rsqrt(2),y=-Rsqrt(2)
Find the zeros of -2y^2+4R^2=0
The zeros of -2y^2+4R^2=0 are y=Rsqrt(2),y=-Rsqrt(2)