What are the solutions to the equation -x^2+3x+28=0 ?

The solutions to the equation -x^2+3x+28=0 are x=-4,x=7

Find the zeros of -x^2+3x+28=0

The zeros of -x^2+3x+28=0 are x=-4,x=7

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- x^{2} + 3 x + 28 = 0

x = - 4, x = 7

Solution steps

- x^{2} + 3 x + 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 28}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 28 = 11

x_{1, 2} = \frac{- 3 \pm 11}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 11}{2 ( - 1 )}, x_{2} = \frac{- 3 - 11}{2 ( - 1 )}

x = \frac{- 3 + 11}{2 ( - 1 )} : - 4

x = \frac{- 3 - 11}{2 ( - 1 )} : 7

The solutions to the quadratic equation are:

x = - 4, x = 7

6 x^{2} + 5 x - 4 = 0

x (x - 3) + 1 = 0

x, f (x + 3) = 4 x^{2} + 3 x - 4

x, 1 - 4 x + 2 x^{2} - 2 y^{3} = 0

y, y^{2} = 2 y

What are the solutions to the equation -x^2+3x+28=0 ?
The solutions to the equation -x^2+3x+28=0 are x=-4,x=7
Find the zeros of -x^2+3x+28=0
The zeros of -x^2+3x+28=0 are x=-4,x=7