What are the solutions to the equation 0=12x^2-24x+8 ?

The solutions to the equation 0=12x^2-24x+8 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3

Find the zeros of 0=12x^2-24x+8

The zeros of 0=12x^2-24x+8 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3

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0 = 12 x^{2} - 24 x + 8

x = \frac{3 + 3}{3}, x = \frac{3 - 3}{3}

Decimal Notation

x = 1.57735 \dots, x = 0.42264 \dots

Solution steps

0 = 12 x^{2} - 24 x + 8

Switch sides

12 x^{2} - 24 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 12 \cdot 8}{2 \cdot 12}

(- 24)^{2} - 4 \cdot 12 \cdot 8 = 83

x_{1, 2} = \frac{- ( - 24 ) \pm 8 3}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 8 3}{2 \cdot 12}, x_{2} = \frac{- ( - 24 ) - 8 3}{2 \cdot 12}

x = \frac{- ( - 24 ) + 8 3}{2 \cdot 12} : \frac{3 + 3}{3}

x = \frac{- ( - 24 ) - 8 3}{2 \cdot 12} : \frac{3 - 3}{3}

The solutions to the quadratic equation are:

x = \frac{3 + 3}{3}, x = \frac{3 - 3}{3}

18 - 2 (x - 5)^{2} = 0

- 5 + x = x^{2}

x^{2} + 1 = 5 x^{2}

5 t^{2} - 2.8 t = 1.1

x, y = - 0.000008 x^{2} + 0.0064 x + 0.2547

What are the solutions to the equation 0=12x^2-24x+8 ?
The solutions to the equation 0=12x^2-24x+8 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3
Find the zeros of 0=12x^2-24x+8
The zeros of 0=12x^2-24x+8 are x=(3+sqrt(3))/3 ,x=(3-sqrt(3))/3