What are the solutions to the equation (x-1)(5x+1)=216 ?

The solutions to the equation (x-1)(5x+1)=216 are x=7,x=-31/5

Find the zeros of (x-1)(5x+1)=216

The zeros of (x-1)(5x+1)=216 are x=7,x=-31/5

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(x - 1) (5 x + 1) = 216

x = 7, x = - \frac{31}{5}

Decimal Notation

x = 7, x = - 6.2

Solution steps

(x - 1) (5 x + 1) = 216

Expand

(x - 1) (5 x + 1) : 5 x^{2} - 4 x - 1

5 x^{2} - 4 x - 1 = 216

Move

216

to the left side

5 x^{2} - 4 x - 217 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 ( - 217 )}{2 \cdot 5}

(- 4)^{2} - 4 \cdot 5 (- 217) = 66

x_{1, 2} = \frac{- ( - 4 ) \pm 66}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 66}{2 \cdot 5}, x_{2} = \frac{- ( - 4 ) - 66}{2 \cdot 5}

x = \frac{- ( - 4 ) + 66}{2 \cdot 5} : 7

x = \frac{- ( - 4 ) - 66}{2 \cdot 5} : - \frac{31}{5}

The solutions to the quadratic equation are:

x = 7, x = - \frac{31}{5}

- 0.5 x^{2} - 30 x + 350 = 0

2.5 x^{2} = 5 x + 50 - 8487.05 - 848.705 x

x^{2} - 39 = - 2 x + 9

3 x^{2} + 5 x + 2

8 z^{2} - 72 = 0

What are the solutions to the equation (x-1)(5x+1)=216 ?
The solutions to the equation (x-1)(5x+1)=216 are x=7,x=-31/5
Find the zeros of (x-1)(5x+1)=216
The zeros of (x-1)(5x+1)=216 are x=7,x=-31/5