What are the solutions to the equation factor x^2-39=-2x+9 ?

The solutions to the equation factor x^2-39=-2x+9 are x=6,x=-8

Find the zeros of factor x^2-39=-2x+9

The zeros of factor x^2-39=-2x+9 are x=6,x=-8

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x^{2} - 39 = - 2 x + 9

x = 6, x = - 8

Solution steps

x^{2} - 39 = - 2 x + 9

Move

9

to the left side

x^{2} - 48 = - 2 x

Move

2 x

to the left side

x^{2} - 48 + 2 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x - 48 = 0

Factor

x^{2} + 2 x - 48 : (x - 6) (x + 8)

(x - 6) (x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 6 = 0 or x + 8 = 0

Solve

x - 6 = 0 : x = 6

Solve

x + 8 = 0 : x = - 8

The solutions to the quadratic equation are:

x = 6, x = - 8

3 x^{2} + 5 x + 2

8 z^{2} - 72 = 0

x, x^{2} + 2 x - 1 = 2

x^{2} = \frac{- b \pm b ^{2} - 4 a c}{2 a}

(3 w - 5) w = 28

What are the solutions to the equation factor x^2-39=-2x+9 ?
The solutions to the equation factor x^2-39=-2x+9 are x=6,x=-8
Find the zeros of factor x^2-39=-2x+9
The zeros of factor x^2-39=-2x+9 are x=6,x=-8