What are the solutions to the equation h^2-7h-8=0 ?

The solutions to the equation h^2-7h-8=0 are h=8,h=-1

Find the zeros of h^2-7h-8=0

The zeros of h^2-7h-8=0 are h=8,h=-1

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h^{2} - 7 h - 8 = 0

h = 8, h = - 1

Solution steps

h^{2} - 7 h - 8 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 8) = 9

h_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 1}

Separate the solutions

h_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 1}, h_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 1}

h = \frac{- ( - 7 ) + 9}{2 \cdot 1} : 8

h = \frac{- ( - 7 ) - 9}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

h = 8, h = - 1

- 28 x^{2} \leq 0

k^{2} + 8 k + 12 = 0

2 x + 6 \geq 9 x - 1

2 - 5 x + 6 = 0

\frac{3}{4} \cdot \frac{4}{3}

What are the solutions to the equation h^2-7h-8=0 ?
The solutions to the equation h^2-7h-8=0 are h=8,h=-1
Find the zeros of h^2-7h-8=0
The zeros of h^2-7h-8=0 are h=8,h=-1