What are the solutions to the equation b^2-1/5 b= 4/5 ?

The solutions to the equation b^2-1/5 b= 4/5 are b=1,b=-4/5

Find the zeros of b^2-1/5 b= 4/5

The zeros of b^2-1/5 b= 4/5 are b=1,b=-4/5

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b^{2} - \frac{1}{5} b = \frac{4}{5}

b = 1, b = - \frac{4}{5}

Decimal Notation

b = 1, b = - 0.8

Solution steps

b^{2} - \frac{1}{5} b = \frac{4}{5}

Multiply both sides by

5

5 b^{2} - b = 4

Move

4

to the left side

5 b^{2} - b - 4 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 ( - 4 )}{2 \cdot 5}

(- 1)^{2} - 4 \cdot 5 (- 4) = 9

b_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 5}

Separate the solutions

b_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 5}, b_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 5}

b = \frac{- ( - 1 ) + 9}{2 \cdot 5} : 1

b = \frac{- ( - 1 ) - 9}{2 \cdot 5} : - \frac{4}{5}

The solutions to the quadratic equation are:

b = 1, b = - \frac{4}{5}

(x + 5)^{2} + 31 = 0

x^{2} - 8 x = 39

6 c^{2} + 8 = c

24 = 4 x^{2} + 2 x + 1

w (2 w + 2) = 40

What are the solutions to the equation b^2-1/5 b= 4/5 ?
The solutions to the equation b^2-1/5 b= 4/5 are b=1,b=-4/5
Find the zeros of b^2-1/5 b= 4/5
The zeros of b^2-1/5 b= 4/5 are b=1,b=-4/5