What are the solutions to the equation w(2w+2)=40 ?

The solutions to the equation w(2w+2)=40 are w=4,w=-5

Find the zeros of w(2w+2)=40

The zeros of w(2w+2)=40 are w=4,w=-5

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w (2 w + 2) = 40

w = 4, w = - 5

Solution steps

w (2 w + 2) = 40

Expand

w (2 w + 2) : 2 w^{2} + 2 w

2 w^{2} + 2 w = 40

Move

40

to the left side

2 w^{2} + 2 w - 40 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 40 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 40) = 18

w_{1, 2} = \frac{- 2 \pm 18}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- 2 + 18}{2 \cdot 2}, w_{2} = \frac{- 2 - 18}{2 \cdot 2}

w = \frac{- 2 + 18}{2 \cdot 2} : 4

w = \frac{- 2 - 18}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

w = 4, w = - 5

16 + x^{2} = 0

9 p^{2} - 27 p + 2 = 0

1 2^{2} = 9^{2} + b^{2}

x^{2} - 49 = 0

9 w^{2} + 25 = 30 w

What are the solutions to the equation w(2w+2)=40 ?
The solutions to the equation w(2w+2)=40 are w=4,w=-5
Find the zeros of w(2w+2)=40
The zeros of w(2w+2)=40 are w=4,w=-5