What are the solutions to the equation 9p^2-27p+2=0 ?

The solutions to the equation 9p^2-27p+2=0 are p=(9+sqrt(73))/6 ,p=(9-sqrt(73))/6

Find the zeros of 9p^2-27p+2=0

The zeros of 9p^2-27p+2=0 are p=(9+sqrt(73))/6 ,p=(9-sqrt(73))/6

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9 p^{2} - 27 p + 2 = 0

p = \frac{9 + 73}{6}, p = \frac{9 - 73}{6}

Decimal Notation

p = 2.92400 \dots, p = 0.07599 \dots

Solution steps

9 p^{2} - 27 p + 2 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 9 \cdot 2}{2 \cdot 9}

(- 27)^{2} - 4 \cdot 9 \cdot 2 = 373

p_{1, 2} = \frac{- ( - 27 ) \pm 3 73}{2 \cdot 9}

Separate the solutions

p_{1} = \frac{- ( - 27 ) + 3 73}{2 \cdot 9}, p_{2} = \frac{- ( - 27 ) - 3 73}{2 \cdot 9}

p = \frac{- ( - 27 ) + 3 73}{2 \cdot 9} : \frac{9 + 73}{6}

p = \frac{- ( - 27 ) - 3 73}{2 \cdot 9} : \frac{9 - 73}{6}

The solutions to the quadratic equation are:

p = \frac{9 + 73}{6}, p = \frac{9 - 73}{6}

1 2^{2} = 9^{2} + b^{2}

x^{2} - 49 = 0

9 w^{2} + 25 = 30 w

x^{2} - 8 x = 84

X^{2} + 4 X - 5 = 0

What are the solutions to the equation 9p^2-27p+2=0 ?
The solutions to the equation 9p^2-27p+2=0 are p=(9+sqrt(73))/6 ,p=(9-sqrt(73))/6
Find the zeros of 9p^2-27p+2=0
The zeros of 9p^2-27p+2=0 are p=(9+sqrt(73))/6 ,p=(9-sqrt(73))/6