What are the solutions to the equation 6x+x^2-13x-18=0 ?

The solutions to the equation 6x+x^2-13x-18=0 are x=9,x=-2

Find the zeros of 6x+x^2-13x-18=0

The zeros of 6x+x^2-13x-18=0 are x=9,x=-2

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6 x + x^{2} - 13 x - 18 = 0

x = 9, x = - 2

Solution steps

6 x + x^{2} - 13 x - 18 = 0

Refine

x^{2} - 7 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 18 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 18) = 11

x_{1, 2} = \frac{- ( - 7 ) \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 11}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 11}{2 \cdot 1}

x = \frac{- ( - 7 ) + 11}{2 \cdot 1} : 9

x = \frac{- ( - 7 ) - 11}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 9, x = - 2

2 x^{2} + 40 x + 32 = 0

6 x^{2} - 4 x = - 2

r, V = π r^{2}

{\frac{3}{2} (p - 2)}^{2}

6^{2} + x^{2} = 100

What are the solutions to the equation 6x+x^2-13x-18=0 ?
The solutions to the equation 6x+x^2-13x-18=0 are x=9,x=-2
Find the zeros of 6x+x^2-13x-18=0
The zeros of 6x+x^2-13x-18=0 are x=9,x=-2