What are the solutions to the equation 24.1=4.9t^2 ?

The solutions to the equation 24.1=4.9t^2 are t=(sqrt(241))/7 ,t=-(sqrt(241))/7

Find the zeros of 24.1=4.9t^2

The zeros of 24.1=4.9t^2 are t=(sqrt(241))/7 ,t=-(sqrt(241))/7

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24.1 = 4.9 t^{2}

t = \frac{241}{7}, t = - \frac{241}{7}

Decimal Notation

t = 2.21773 \dots, t = - 2.21773 \dots

Solution steps

24.1 = 4.9 t^{2}

Switch sides

4.9 t^{2} = 24.1

Multiply both sides by

10

49 t^{2} = 241

Divide both sides by

49

t^{2} = \frac{241}{49}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = \frac{241}{49}, t = - \frac{241}{49}

\frac{241}{49} = \frac{241}{7}

- \frac{241}{49} = - \frac{241}{7}

t = \frac{241}{7}, t = - \frac{241}{7}

x^{2} + \frac{5}{100} x + \frac{4}{10000} = 0

x^{2} + 9 x + 9 + 8 = 0

5 y^{2} + 10 y + 4 = 0

x^{2} + (- 2 x + c)^{2} - 10 x - 8 (- 2 x + c) + 21 = 0

- 5 y - 3 = 2 y^{2}

What are the solutions to the equation 24.1=4.9t^2 ?
The solutions to the equation 24.1=4.9t^2 are t=(sqrt(241))/7 ,t=-(sqrt(241))/7
Find the zeros of 24.1=4.9t^2
The zeros of 24.1=4.9t^2 are t=(sqrt(241))/7 ,t=-(sqrt(241))/7