What are the solutions to the equation c^2=4+25 ?

The solutions to the equation c^2=4+25 are c=sqrt(29),c=-sqrt(29)

Find the zeros of c^2=4+25

The zeros of c^2=4+25 are c=sqrt(29),c=-sqrt(29)

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c^{2} = 4 + 25

c = 29, c = - 29

Decimal Notation

c = 5.38516 \dots, c = - 5.38516 \dots

Solution steps

c^{2} = 4 + 25

Add the numbers:

4 + 25 = 29

c^{2} = 29

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 29, c = - 29

20 (x^{2} - 2 x + 1) = x

x, z = 36 - 3 x^{2} - 3 y^{2}

(x - 8) (3 x + 5) = 0

b = x^{2}

- 45 x^{2} + 250 x + 250 = 0

What are the solutions to the equation c^2=4+25 ?
The solutions to the equation c^2=4+25 are c=sqrt(29),c=-sqrt(29)
Find the zeros of c^2=4+25
The zeros of c^2=4+25 are c=sqrt(29),c=-sqrt(29)