What are the solutions to the equation -45x^2+250x+250=0 ?

The solutions to the equation -45x^2+250x+250=0 are x=-(5(sqrt(43)-5))/9 ,x=(5(5+sqrt(43)))/9

Find the zeros of -45x^2+250x+250=0

The zeros of -45x^2+250x+250=0 are x=-(5(sqrt(43)-5))/9 ,x=(5(5+sqrt(43)))/9

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- 45 x^{2} + 250 x + 250 = 0

x = - \frac{5 ( 43 - 5 )}{9}, x = \frac{5 ( 5 + 43 )}{9}

Decimal Notation

x = - 0.86524 \dots, x = 6.42079 \dots

Solution steps

- 45 x^{2} + 250 x + 250 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 250 \pm 25 0 ^{2} - 4 ( - 45 ) \cdot 250}{2 ( - 45 )}

25 0^{2} - 4 (- 45) \cdot 250 = 5043

x_{1, 2} = \frac{- 250 \pm 50 43}{2 ( - 45 )}

Separate the solutions

x_{1} = \frac{- 250 + 50 43}{2 ( - 45 )}, x_{2} = \frac{- 250 - 50 43}{2 ( - 45 )}

x = \frac{- 250 + 50 43}{2 ( - 45 )} : - \frac{5 ( 43 - 5 )}{9}

x = \frac{- 250 - 50 43}{2 ( - 45 )} : \frac{5 ( 5 + 43 )}{9}

The solutions to the quadratic equation are:

x = - \frac{5 ( 43 - 5 )}{9}, x = \frac{5 ( 5 + 43 )}{9}

x, y = x^{2} + 2 x + 4

26 x^{2} + 138 x + 213 = 0

9 x^{2} + 240 x - 4800 = 0

- x^{2} - x + 6 = 0

x^{2} + 12 x + \frac{1}{3} = 0

What are the solutions to the equation -45x^2+250x+250=0 ?
The solutions to the equation -45x^2+250x+250=0 are x=-(5(sqrt(43)-5))/9 ,x=(5(5+sqrt(43)))/9
Find the zeros of -45x^2+250x+250=0
The zeros of -45x^2+250x+250=0 are x=-(5(sqrt(43)-5))/9 ,x=(5(5+sqrt(43)))/9