What are the solutions to the equation 9x^2+240x-4800=0 ?

The solutions to the equation 9x^2+240x-4800=0 are x= 40/3 ,x=-40

Find the zeros of 9x^2+240x-4800=0

The zeros of 9x^2+240x-4800=0 are x= 40/3 ,x=-40

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9 x^{2} + 240 x - 4800 = 0

x = \frac{40}{3}, x = - 40

Decimal Notation

x = 13.33333 \dots, x = - 40

Solution steps

9 x^{2} + 240 x - 4800 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 240 \pm 24 0 ^{2} - 4 \cdot 9 ( - 4800 )}{2 \cdot 9}

24 0^{2} - 4 \cdot 9 (- 4800) = 480

x_{1, 2} = \frac{- 240 \pm 480}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 240 + 480}{2 \cdot 9}, x_{2} = \frac{- 240 - 480}{2 \cdot 9}

x = \frac{- 240 + 480}{2 \cdot 9} : \frac{40}{3}

x = \frac{- 240 - 480}{2 \cdot 9} : - 40

The solutions to the quadratic equation are:

x = \frac{40}{3}, x = - 40

- x^{2} - x + 6 = 0

x^{2} + 12 x + \frac{1}{3} = 0

y^{2} = 18 y + 18

7 v^{2} = - 35 v + 168

(11 m + 2 - 4 m^{2})^{2} - 4 (m^{2} + 2) (4 m^{2} + 26 - 22 m) = 0

What are the solutions to the equation 9x^2+240x-4800=0 ?
The solutions to the equation 9x^2+240x-4800=0 are x= 40/3 ,x=-40
Find the zeros of 9x^2+240x-4800=0
The zeros of 9x^2+240x-4800=0 are x= 40/3 ,x=-40