What are the solutions to the equation 4x^2+5x-26x= 13/4 ?

The solutions to the equation 4x^2+5x-26x= 13/4 are x=(21+sqrt(493))/8 ,x=(21-sqrt(493))/8

Find the zeros of 4x^2+5x-26x= 13/4

The zeros of 4x^2+5x-26x= 13/4 are x=(21+sqrt(493))/8 ,x=(21-sqrt(493))/8

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4 x^{2} + 5 x - 26 x = \frac{13}{4}

x = \frac{21 + 493}{8}, x = \frac{21 - 493}{8}

Decimal Notation

x = 5.40045 \dots, x = - 0.15045 \dots

Solution steps

4 x^{2} + 5 x - 26 x = \frac{13}{4}

Multiply both sides by

4

16 x^{2} + 20 x - 104 x = 13

16 x^{2} - 84 x = 13

Move

13

to the left side

16 x^{2} - 84 x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 84 ) \pm ( - 84 ) ^{2} - 4 \cdot 16 ( - 13 )}{2 \cdot 16}

(- 84)^{2} - 4 \cdot 16 (- 13) = 4493

x_{1, 2} = \frac{- ( - 84 ) \pm 4 493}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 84 ) + 4 493}{2 \cdot 16}, x_{2} = \frac{- ( - 84 ) - 4 493}{2 \cdot 16}

x = \frac{- ( - 84 ) + 4 493}{2 \cdot 16} : \frac{21 + 493}{8}

x = \frac{- ( - 84 ) - 4 493}{2 \cdot 16} : \frac{21 - 493}{8}

The solutions to the quadratic equation are:

x = \frac{21 + 493}{8}, x = \frac{21 - 493}{8}

- 15 - 7 x + 2 x^{2} = 0

2 x^{2} = - 8 x - 3

x^{2} + 2 x + 80 = 0

y^{2} - 6 y = 9

x^{2} - 2 x - 4 = 6 x + 5

What are the solutions to the equation 4x^2+5x-26x= 13/4 ?
The solutions to the equation 4x^2+5x-26x= 13/4 are x=(21+sqrt(493))/8 ,x=(21-sqrt(493))/8
Find the zeros of 4x^2+5x-26x= 13/4
The zeros of 4x^2+5x-26x= 13/4 are x=(21+sqrt(493))/8 ,x=(21-sqrt(493))/8