What are the solutions to the equation y^2-6y=9 ?

The solutions to the equation y^2-6y=9 are y=3(1+sqrt(2)),y=3(1-sqrt(2))

Find the zeros of y^2-6y=9

The zeros of y^2-6y=9 are y=3(1+sqrt(2)),y=3(1-sqrt(2))

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y^{2} - 6 y = 9

y = 3 (1 + 2), y = 3 (1 - 2)

Decimal Notation

y = 7.24264 \dots, y = - 1.24264 \dots

Solution steps

y^{2} - 6 y = 9

Move

9

to the left side

y^{2} - 6 y - 9 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 9) = 62

y_{1, 2} = \frac{- ( - 6 ) \pm 6 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 6 2}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 6 2}{2 \cdot 1}

y = \frac{- ( - 6 ) + 6 2}{2 \cdot 1} : 3 (1 + 2)

y = \frac{- ( - 6 ) - 6 2}{2 \cdot 1} : 3 (1 - 2)

The solutions to the quadratic equation are:

y = 3 (1 + 2), y = 3 (1 - 2)

x^{2} - 2 x - 4 = 6 x + 5

(2 a + 1)^{2} = a^{2} + (2 a - 1)^{2}

(3 + x)^{2} + (13 + x^{2}) = 256

(3 x + 2) (x + 3) = 0

x^{2} - 23.5 x - 1.75 = 0

What are the solutions to the equation y^2-6y=9 ?
The solutions to the equation y^2-6y=9 are y=3(1+sqrt(2)),y=3(1-sqrt(2))
Find the zeros of y^2-6y=9
The zeros of y^2-6y=9 are y=3(1+sqrt(2)),y=3(1-sqrt(2))