What are the solutions to the equation 5a^2+2a-33=0 ?

The solutions to the equation 5a^2+2a-33=0 are a=(-1+sqrt(166))/5 ,a=-(1+sqrt(166))/5

Find the zeros of 5a^2+2a-33=0

The zeros of 5a^2+2a-33=0 are a=(-1+sqrt(166))/5 ,a=-(1+sqrt(166))/5

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5 a^{2} + 2 a - 33 = 0

a = \frac{- 1 + 166}{5}, a = - \frac{1 + 166}{5}

Decimal Notation

a = 2.37681 \dots, a = - 2.77681 \dots

Solution steps

5 a^{2} + 2 a - 33 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 5 ( - 33 )}{2 \cdot 5}

2^{2} - 4 \cdot 5 (- 33) = 2166

a_{1, 2} = \frac{- 2 \pm 2 166}{2 \cdot 5}

Separate the solutions

a_{1} = \frac{- 2 + 2 166}{2 \cdot 5}, a_{2} = \frac{- 2 - 2 166}{2 \cdot 5}

a = \frac{- 2 + 2 166}{2 \cdot 5} : \frac{- 1 + 166}{5}

a = \frac{- 2 - 2 166}{2 \cdot 5} : - \frac{1 + 166}{5}

The solutions to the quadratic equation are:

a = \frac{- 1 + 166}{5}, a = - \frac{1 + 166}{5}

a^{2} + 3 a + 1 = 0

b^{2} + 8 b + 7 = 0

(1) = x^{2}

2 r^{2} + 12 r + 10 = 0

(1 - 0.0038)^{5} = (1 - 0.0054)^{3} (1 + x)^{2}

What are the solutions to the equation 5a^2+2a-33=0 ?
The solutions to the equation 5a^2+2a-33=0 are a=(-1+sqrt(166))/5 ,a=-(1+sqrt(166))/5
Find the zeros of 5a^2+2a-33=0
The zeros of 5a^2+2a-33=0 are a=(-1+sqrt(166))/5 ,a=-(1+sqrt(166))/5