What are the solutions to the equation x^2+8x+16=x+10 ?

The solutions to the equation x^2+8x+16=x+10 are x=-1,x=-6

Find the zeros of x^2+8x+16=x+10

The zeros of x^2+8x+16=x+10 are x=-1,x=-6

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x^{2} + 8 x + 16 = x + 10

x = - 1, x = - 6

Solution steps

x^{2} + 8 x + 16 = x + 10

Move

10

to the left side

x^{2} + 8 x + 6 = x

Move

x

to the left side

x^{2} + 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 6 = 5

x_{1, 2} = \frac{- 7 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 5}{2 \cdot 1}, x_{2} = \frac{- 7 - 5}{2 \cdot 1}

x = \frac{- 7 + 5}{2 \cdot 1} : - 1

x = \frac{- 7 - 5}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = - 1, x = - 6

15 + 4 x - 2 x^{2} = 12

3 x^{2} + 18 x + 2 l x = 0, 12 y + 2 l y = 0, x^{2} + y^{2} = 9

\frac{0.01478 \cdot 2000 \cdot x ^{2}}{2 \cdot 9.81 \cdot 0.16} = 35

c^{2} = 1^{2} + x^{2}

10 x^{2} + 37 x + 7 = 0

What are the solutions to the equation x^2+8x+16=x+10 ?
The solutions to the equation x^2+8x+16=x+10 are x=-1,x=-6
Find the zeros of x^2+8x+16=x+10
The zeros of x^2+8x+16=x+10 are x=-1,x=-6