What are the solutions to the equation c^2=1^2+x^2 ?

The solutions to the equation c^2=1^2+x^2 are x=sqrt(c^2-1),x=-sqrt(c^2-1)

Find the zeros of c^2=1^2+x^2

The zeros of c^2=1^2+x^2 are x=sqrt(c^2-1),x=-sqrt(c^2-1)

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c^{2} = 1^{2} + x^{2}

x = c^{2} - 1, x = - c^{2} - 1

Solution steps

c^{2} = 1^{2} + x^{2}

Switch sides

1^{2} + x^{2} = c^{2}

Move

1^{2}

to the right side

x^{2} = c^{2} - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = c^{2} - 1, x = - c^{2} - 1

10 x^{2} + 37 x + 7 = 0

- 4 = x^{2} - x - 6

a^{2} - 6 a - 27 = 0

80 x - 16 x^{2} = 96

4 y^{2} - 2400 y + 1442000 = 0

What are the solutions to the equation c^2=1^2+x^2 ?
The solutions to the equation c^2=1^2+x^2 are x=sqrt(c^2-1),x=-sqrt(c^2-1)
Find the zeros of c^2=1^2+x^2
The zeros of c^2=1^2+x^2 are x=sqrt(c^2-1),x=-sqrt(c^2-1)