What are the solutions to the equation -4+v-v^2=0 ?

The solutions to the equation -4+v-v^2=0 are v= 1/2-i(sqrt(15))/2 ,v= 1/2+i(sqrt(15))/2

Find the zeros of -4+v-v^2=0

The zeros of -4+v-v^2=0 are v= 1/2-i(sqrt(15))/2 ,v= 1/2+i(sqrt(15))/2

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- 4 + v - v^{2} = 0

v = \frac{1}{2} - i \frac{15}{2}, v = \frac{1}{2} + i \frac{15}{2}

Solution steps

- 4 + v - v^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- v^{2} + v - 4 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) ( - 4 )}{2 ( - 1 )}

Simplify

1^{2} - 4 (- 1) (- 4) : 15 i

v_{1, 2} = \frac{- 1 \pm 15 i}{2 ( - 1 )}

Separate the solutions

v_{1} = \frac{- 1 + 15 i}{2 ( - 1 )}, v_{2} = \frac{- 1 - 15 i}{2 ( - 1 )}

v = \frac{- 1 + 15 i}{2 ( - 1 )} : \frac{1}{2} - i \frac{15}{2}

v = \frac{- 1 - 15 i}{2 ( - 1 )} : \frac{1}{2} + i \frac{15}{2}

The solutions to the quadratic equation are:

v = \frac{1}{2} - i \frac{15}{2}, v = \frac{1}{2} + i \frac{15}{2}

(x) = x^{2} - x + 10

x^{2} + (- \frac{12}{13})^{2} = 1

x, - x^{2} - y^{2} + z^{2} = 1

1000000 = 100000 + 1200 x + 200 x^{2}

x, x^{2} + y^{2} - 2 x + 2 = 0

What are the solutions to the equation -4+v-v^2=0 ?
The solutions to the equation -4+v-v^2=0 are v= 1/2-i(sqrt(15))/2 ,v= 1/2+i(sqrt(15))/2
Find the zeros of -4+v-v^2=0
The zeros of -4+v-v^2=0 are v= 1/2-i(sqrt(15))/2 ,v= 1/2+i(sqrt(15))/2