What are the solutions to the equation 3q^2-80q+430=0 ?

The solutions to the equation 3q^2-80q+430=0 are q=(40+sqrt(310))/3 ,q=(40-sqrt(310))/3

Find the zeros of 3q^2-80q+430=0

The zeros of 3q^2-80q+430=0 are q=(40+sqrt(310))/3 ,q=(40-sqrt(310))/3

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3 q^{2} - 80 q + 430 = 0

q = \frac{40 + 310}{3}, q = \frac{40 - 310}{3}

Decimal Notation

q = 19.20227 \dots, q = 7.46439 \dots

Solution steps

3 q^{2} - 80 q + 430 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 80 ) \pm ( - 80 ) ^{2} - 4 \cdot 3 \cdot 430}{2 \cdot 3}

(- 80)^{2} - 4 \cdot 3 \cdot 430 = 2310

q_{1, 2} = \frac{- ( - 80 ) \pm 2 310}{2 \cdot 3}

Separate the solutions

q_{1} = \frac{- ( - 80 ) + 2 310}{2 \cdot 3}, q_{2} = \frac{- ( - 80 ) - 2 310}{2 \cdot 3}

q = \frac{- ( - 80 ) + 2 310}{2 \cdot 3} : \frac{40 + 310}{3}

q = \frac{- ( - 80 ) - 2 310}{2 \cdot 3} : \frac{40 - 310}{3}

The solutions to the quadratic equation are:

q = \frac{40 + 310}{3}, q = \frac{40 - 310}{3}

x^{2} = 6^{2} + 4^{2}

2.5 \cdot 1 0^{- 9} = (0.072 - x) \cdot (0.04 - x)

x, x^{2} + 2 y^{2} + 3 = 0

17 - 2 y = y^{2} - 7

b (b - 4) = 0

What are the solutions to the equation 3q^2-80q+430=0 ?
The solutions to the equation 3q^2-80q+430=0 are q=(40+sqrt(310))/3 ,q=(40-sqrt(310))/3
Find the zeros of 3q^2-80q+430=0
The zeros of 3q^2-80q+430=0 are q=(40+sqrt(310))/3 ,q=(40-sqrt(310))/3