What are the solutions to the equation 1596=0.5x^2+0.5x ?

The solutions to the equation 1596=0.5x^2+0.5x are x=56,x=-57

Find the zeros of 1596=0.5x^2+0.5x

The zeros of 1596=0.5x^2+0.5x are x=56,x=-57

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1596 = 0.5 x^{2} + 0.5 x

x = 56, x = - 57

Solution steps

1596 = 0.5 x^{2} + 0.5 x

Multiply both sides by

10

15960 = 5 x^{2} + 5 x

Switch sides

5 x^{2} + 5 x = 15960

Move

15960

to the left side

5 x^{2} + 5 x - 15960 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 5 ( - 15960 )}{2 \cdot 5}

5^{2} - 4 \cdot 5 (- 15960) = 565

x_{1, 2} = \frac{- 5 \pm 565}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 5 + 565}{2 \cdot 5}, x_{2} = \frac{- 5 - 565}{2 \cdot 5}

x = \frac{- 5 + 565}{2 \cdot 5} : 56

x = \frac{- 5 - 565}{2 \cdot 5} : - 57

The solutions to the quadratic equation are:

x = 56, x = - 57

18 = 0.5527 x^{2} - 8.5491 x + 47.273

c^{2} = 2^{2} + 3^{2}

x, (\frac{5}{4} x y + y - 1) (3 x + 2) = 2 y - 3 x - \frac{1}{2}

x^{2} + 2 = 9

x^{2} + 2 = 4

What are the solutions to the equation 1596=0.5x^2+0.5x ?
The solutions to the equation 1596=0.5x^2+0.5x are x=56,x=-57
Find the zeros of 1596=0.5x^2+0.5x
The zeros of 1596=0.5x^2+0.5x are x=56,x=-57