What are the solutions to the equation 12^2=x^2+8^2 ?

The solutions to the equation 12^2=x^2+8^2 are x=4sqrt(5),x=-4sqrt(5)

Find the zeros of 12^2=x^2+8^2

The zeros of 12^2=x^2+8^2 are x=4sqrt(5),x=-4sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 2^{2} = x^{2} + 8^{2}

x = 45, x = - 45

Decimal Notation

x = 8.94427 \dots, x = - 8.94427 \dots

Solution steps

1 2^{2} = x^{2} + 8^{2}

Switch sides

x^{2} + 8^{2} = 1 2^{2}

Move

8^{2}

to the right side

x^{2} = 80

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 80, x = - 80

80 = 45

- 80 = - 45

x = 45, x = - 45

x, x^{2} + y^{2} + 10 x - 4 y + 33 = 0

(x - 4)^{2} + (- x + 8)^{2} = 16

a^{2} - 2 a + 4 = 0

3 \cdot 3.14 = 3.14 \cdot x^{2}

x^{2} + 6 x + 10 = 0

What are the solutions to the equation 12^2=x^2+8^2 ?
The solutions to the equation 12^2=x^2+8^2 are x=4sqrt(5),x=-4sqrt(5)
Find the zeros of 12^2=x^2+8^2
The zeros of 12^2=x^2+8^2 are x=4sqrt(5),x=-4sqrt(5)