What are the solutions to the equation a^2-2a+4=0 ?

The solutions to the equation a^2-2a+4=0 are a=1+sqrt(3)i,a=1-sqrt(3)i

Find the zeros of a^2-2a+4=0

The zeros of a^2-2a+4=0 are a=1+sqrt(3)i,a=1-sqrt(3)i

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a^{2} - 2 a + 4 = 0

a = 1 + 3 i, a = 1 - 3 i

Solution steps

a^{2} - 2 a + 4 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 4 : 23 i

a_{1, 2} = \frac{- ( - 2 ) \pm 2 3 i}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 2 ) + 2 3 i}{2 \cdot 1}, a_{2} = \frac{- ( - 2 ) - 2 3 i}{2 \cdot 1}

a = \frac{- ( - 2 ) + 2 3 i}{2 \cdot 1} : 1 + 3 i

a = \frac{- ( - 2 ) - 2 3 i}{2 \cdot 1} : 1 - 3 i

The solutions to the quadratic equation are:

a = 1 + 3 i, a = 1 - 3 i

3 \cdot 3.14 = 3.14 \cdot x^{2}

x^{2} + 6 x + 10 = 0

4 t^{2} - 15 t + 10 = 0

5 w^{2} = 17 w - 6

9 x^{2} - 71 x = 8

What are the solutions to the equation a^2-2a+4=0 ?
The solutions to the equation a^2-2a+4=0 are a=1+sqrt(3)i,a=1-sqrt(3)i
Find the zeros of a^2-2a+4=0
The zeros of a^2-2a+4=0 are a=1+sqrt(3)i,a=1-sqrt(3)i