What are the solutions to the equation 9x^2-71x=8 ?

The solutions to the equation 9x^2-71x=8 are x=8,x=-1/9

Find the zeros of 9x^2-71x=8

The zeros of 9x^2-71x=8 are x=8,x=-1/9

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9 x^{2} - 71 x = 8

x = 8, x = - \frac{1}{9}

Decimal Notation

x = 8, x = - 0.11111 \dots

Solution steps

9 x^{2} - 71 x = 8

Move

8

to the left side

9 x^{2} - 71 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 71 ) \pm ( - 71 ) ^{2} - 4 \cdot 9 ( - 8 )}{2 \cdot 9}

(- 71)^{2} - 4 \cdot 9 (- 8) = 73

x_{1, 2} = \frac{- ( - 71 ) \pm 73}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 71 ) + 73}{2 \cdot 9}, x_{2} = \frac{- ( - 71 ) - 73}{2 \cdot 9}

x = \frac{- ( - 71 ) + 73}{2 \cdot 9} : 8

x = \frac{- ( - 71 ) - 73}{2 \cdot 9} : - \frac{1}{9}

The solutions to the quadratic equation are:

x = 8, x = - \frac{1}{9}

3 s^{2} + 40 s + 64 = 0

2 x^{2} + 15 x - 192 = 0

16 x^{2} - 80 x + 64 = 0

(x - 5)^{2} = (x + 5)^{2} - 3 x^{2} - 25

4 x^{2} = 28 x - 49

What are the solutions to the equation 9x^2-71x=8 ?
The solutions to the equation 9x^2-71x=8 are x=8,x=-1/9
Find the zeros of 9x^2-71x=8
The zeros of 9x^2-71x=8 are x=8,x=-1/9