What are the solutions to the equation (y-2)^2=3 ?

The solutions to the equation (y-2)^2=3 are y=sqrt(3)+2,y=-sqrt(3)+2

Find the zeros of (y-2)^2=3

The zeros of (y-2)^2=3 are y=sqrt(3)+2,y=-sqrt(3)+2

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(y - 2)^{2} = 3

y = 3 + 2, y = - 3 + 2

Decimal Notation

y = 3.73205 \dots, y = 0.26794 \dots

Solution steps

(y - 2)^{2} = 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 2 = 3 : y = 3 + 2

Solve

y - 2 = - 3 : y = - 3 + 2

The solutions to the quadratic equation are:

y = 3 + 2, y = - 3 + 2

(y - 2)^{2} = 1

x^{2} - 36 = 0

x^{2} - 5 x - 250 = 0

0.02844 x^{2} - 0.1596 x + 0.218 = 0

c^{2} = 5^{2} + 1 1^{2}

What are the solutions to the equation (y-2)^2=3 ?
The solutions to the equation (y-2)^2=3 are y=sqrt(3)+2,y=-sqrt(3)+2
Find the zeros of (y-2)^2=3
The zeros of (y-2)^2=3 are y=sqrt(3)+2,y=-sqrt(3)+2