What are the solutions to the equation 5x+3x-6+2x^2-4=-6 ?

The solutions to the equation 5x+3x-6+2x^2-4=-6 are x=-2+sqrt(6),x=-2-sqrt(6)

Find the zeros of 5x+3x-6+2x^2-4=-6

The zeros of 5x+3x-6+2x^2-4=-6 are x=-2+sqrt(6),x=-2-sqrt(6)

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5 x + 3 x - 6 + 2 x^{2} - 4 = - 6

x = - 2 + 6, x = - 2 - 6

Decimal Notation

x = 0.44948 \dots, x = - 4.44948 \dots

Solution steps

5 x + 3 x - 6 + 2 x^{2} - 4 = - 6

Refine

2 x^{2} + 8 x - 10 = - 6

Move

6

to the left side

2 x^{2} + 8 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 4) = 46

x_{1, 2} = \frac{- 8 \pm 4 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 4 6}{2 \cdot 2}, x_{2} = \frac{- 8 - 4 6}{2 \cdot 2}

x = \frac{- 8 + 4 6}{2 \cdot 2} : - 2 + 6

x = \frac{- 8 - 4 6}{2 \cdot 2} : - 2 - 6

The solutions to the quadratic equation are:

x = - 2 + 6, x = - 2 - 6

a^{2} + 576 = 625

9 m^{2} - 58 m + 24 = 0

0 = 5 x^{2} - 90

k^{2} - 10 k + 15 = 0

x^{2} - 300 x + 18900 = 0

What are the solutions to the equation 5x+3x-6+2x^2-4=-6 ?
The solutions to the equation 5x+3x-6+2x^2-4=-6 are x=-2+sqrt(6),x=-2-sqrt(6)
Find the zeros of 5x+3x-6+2x^2-4=-6
The zeros of 5x+3x-6+2x^2-4=-6 are x=-2+sqrt(6),x=-2-sqrt(6)