What are the solutions to the equation (200+20x)(40-2x)=9000 ?

The solutions to the equation (200+20x)(40-2x)=9000 are x=5

Find the zeros of (200+20x)(40-2x)=9000

The zeros of (200+20x)(40-2x)=9000 are x=5

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(200 + 20 x) (40 - 2 x) = 9000

x = 5

Solution steps

(200 + 20 x) (40 - 2 x) = 9000

Expand

(200 + 20 x) (40 - 2 x) : 8000 + 400 x - 40 x^{2}

8000 + 400 x - 40 x^{2} = 9000

Move

9000

to the left side

- 40 x^{2} + 400 x - 1000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 400 \pm 40 0 ^{2} - 4 ( - 40 ) ( - 1000 )}{2 ( - 40 )}

40 0^{2} - 4 (- 40) (- 1000) = 0

x_{1, 2} = \frac{- 400 \pm 0}{2 ( - 40 )}

x = \frac{- 400}{2 ( - 40 )}

\frac{- 400}{2 ( - 40 )} = 5

x = 5

The solution to the quadratic equation is:

x = 5

t = \frac{1}{2} \cdot (- 9.81) \cdot t^{2} + 20 \cdot t + 5

- 4 d^{2} - d + 3 = 0

40 x = - 1000 + 25 x + \frac{1}{2} (1.5) x^{2}

y = 3 x^{2} - 5 x - 4, x

2 r^{2} - 3 r - 8 = 0

What are the solutions to the equation (200+20x)(40-2x)=9000 ?
The solutions to the equation (200+20x)(40-2x)=9000 are x=5
Find the zeros of (200+20x)(40-2x)=9000
The zeros of (200+20x)(40-2x)=9000 are x=5