What are the solutions to the equation -4d^2-d+3=0 ?

The solutions to the equation -4d^2-d+3=0 are d=-1,d= 3/4

Find the zeros of -4d^2-d+3=0

The zeros of -4d^2-d+3=0 are d=-1,d= 3/4

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- 4 d^{2} - d + 3 = 0

d = - 1, d = \frac{3}{4}

Decimal Notation

d = - 1, d = 0.75

Solution steps

- 4 d^{2} - d + 3 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 4 ) \cdot 3}{2 ( - 4 )}

(- 1)^{2} - 4 (- 4) \cdot 3 = 7

d_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 ( - 4 )}

Separate the solutions

d_{1} = \frac{- ( - 1 ) + 7}{2 ( - 4 )}, d_{2} = \frac{- ( - 1 ) - 7}{2 ( - 4 )}

d = \frac{- ( - 1 ) + 7}{2 ( - 4 )} : - 1

d = \frac{- ( - 1 ) - 7}{2 ( - 4 )} : \frac{3}{4}

The solutions to the quadratic equation are:

d = - 1, d = \frac{3}{4}

40 x = - 1000 + 25 x + \frac{1}{2} (1.5) x^{2}

y = 3 x^{2} - 5 x - 4, x

2 r^{2} - 3 r - 8 = 0

- 5 w^{2} + 9 w + 1 = - 6 w^{2}

(x - 1)^{2} = x - 3 (x - 3 + 5)

What are the solutions to the equation -4d^2-d+3=0 ?
The solutions to the equation -4d^2-d+3=0 are d=-1,d= 3/4
Find the zeros of -4d^2-d+3=0
The zeros of -4d^2-d+3=0 are d=-1,d= 3/4