What are the solutions to the equation (x-1)^2=x-3(x-3+5) ?

The solutions to the equation (x-1)^2=x-3(x-3+5) are x=sqrt(7)i,x=-sqrt(7)i

Find the zeros of (x-1)^2=x-3(x-3+5)

The zeros of (x-1)^2=x-3(x-3+5) are x=sqrt(7)i,x=-sqrt(7)i

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(x - 1)^{2} = x - 3 (x - 3 + 5)

x = 7 i, x = - 7 i

Solution steps

(x - 1)^{2} = x - 3 (x - 3 + 5)

Expand

(x - 1)^{2} : x^{2} - 2 x + 1

Expand

x - 3 (x - 3 + 5) : - 2 x - 6

x^{2} - 2 x + 1 = - 2 x - 6

Move

1

to the right side

x^{2} - 2 x = - 2 x - 7

Move

2 x

to the left side

x^{2} = - 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 7, x = - - 7

- 7 = 7 i

- - 7 = - 7 i

x = 7 i, x = - 7 i

- 4 x^{2} + 3 x + 7 = 0

x^{2} = 5 \cdot 15

x^{2} + 6 x - 2 = 0

x, x^{2} + 4 x y - 4 y^{2} - 3 x + 4 y - 10 = 0

\frac{0.011 \cdot 2000 \cdot x ^{2}}{2 \cdot 9.81 \cdot 0.16} = 35

What are the solutions to the equation (x-1)^2=x-3(x-3+5) ?
The solutions to the equation (x-1)^2=x-3(x-3+5) are x=sqrt(7)i,x=-sqrt(7)i
Find the zeros of (x-1)^2=x-3(x-3+5)
The zeros of (x-1)^2=x-3(x-3+5) are x=sqrt(7)i,x=-sqrt(7)i