What are the solutions to the equation 2X^2+13X=7 ?

The solutions to the equation 2X^2+13X=7 are X= 1/2 ,X=-7

Find the zeros of 2X^2+13X=7

The zeros of 2X^2+13X=7 are X= 1/2 ,X=-7

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2 X^{2} + 13 X = 7

X = \frac{1}{2}, X = - 7

Decimal Notation

X = 0.5, X = - 7

Solution steps

2 X^{2} + 13 X = 7

Move

7

to the left side

2 X^{2} + 13 X - 7 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 (- 7) = 15

X_{1, 2} = \frac{- 13 \pm 15}{2 \cdot 2}

Separate the solutions

X_{1} = \frac{- 13 + 15}{2 \cdot 2}, X_{2} = \frac{- 13 - 15}{2 \cdot 2}

X = \frac{- 13 + 15}{2 \cdot 2} : \frac{1}{2}

X = \frac{- 13 - 15}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

X = \frac{1}{2}, X = - 7

x^{2} - 5 x + 6 = 4

x^{2} - 5 x + 6 = 9

2 r^{2} - 72 = 0

- 3 x^{2} + 12 x - 5 = 0

2 x^{2} - 10 x + 8

What are the solutions to the equation 2X^2+13X=7 ?
The solutions to the equation 2X^2+13X=7 are X= 1/2 ,X=-7
Find the zeros of 2X^2+13X=7
The zeros of 2X^2+13X=7 are X= 1/2 ,X=-7