What are the solutions to the equation x^2-7x+42=0 ?

The solutions to the equation x^2-7x+42=0 are x= 7/2+i(sqrt(119))/2 ,x= 7/2-i(sqrt(119))/2

Find the zeros of x^2-7x+42=0

The zeros of x^2-7x+42=0 are x= 7/2+i(sqrt(119))/2 ,x= 7/2-i(sqrt(119))/2

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x^{2} - 7 x + 42 = 0

x = \frac{7}{2} + i \frac{119}{2}, x = \frac{7}{2} - i \frac{119}{2}

Solution steps

x^{2} - 7 x + 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 42}{2 \cdot 1}

Simplify

(- 7)^{2} - 4 \cdot 1 \cdot 42 : 119 i

x_{1, 2} = \frac{- ( - 7 ) \pm 119 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 119 i}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 119 i}{2 \cdot 1}

x = \frac{- ( - 7 ) + 119 i}{2 \cdot 1} : \frac{7}{2} + i \frac{119}{2}

x = \frac{- ( - 7 ) - 119 i}{2 \cdot 1} : \frac{7}{2} - i \frac{119}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2} + i \frac{119}{2}, x = \frac{7}{2} - i \frac{119}{2}

x, x^{2} + K x + 9 = 0

x, 9 x^{2} - 4 y^{2} - z^{2} + 16 y - 17 = 0

16 x^{2} - 23 x = 17 x - 25

9 y^{2} - y = 0

x, 3 x y - 5 x^{2} - y^{2} = 3

What are the solutions to the equation x^2-7x+42=0 ?
The solutions to the equation x^2-7x+42=0 are x= 7/2+i(sqrt(119))/2 ,x= 7/2-i(sqrt(119))/2
Find the zeros of x^2-7x+42=0
The zeros of x^2-7x+42=0 are x= 7/2+i(sqrt(119))/2 ,x= 7/2-i(sqrt(119))/2