What are the solutions to the equation 9y^2-y=0 ?

The solutions to the equation 9y^2-y=0 are y= 1/9 ,y=0

Find the zeros of 9y^2-y=0

The zeros of 9y^2-y=0 are y= 1/9 ,y=0

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9 y^{2} - y = 0

y = \frac{1}{9}, y = 0

Decimal Notation

y = 0.11111 \dots, y = 0

Solution steps

9 y^{2} - y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 9 \cdot 0}{2 \cdot 9}

(- 1)^{2} - 4 \cdot 9 \cdot 0 = 1

y_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 9}

Separate the solutions

y_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 9}, y_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 9}

y = \frac{- ( - 1 ) + 1}{2 \cdot 9} : \frac{1}{9}

y = \frac{- ( - 1 ) - 1}{2 \cdot 9} : 0

The solutions to the quadratic equation are:

y = \frac{1}{9}, y = 0

x, 3 x y - 5 x^{2} - y^{2} = 3

x^{2} - 4 x - 26 = - 2

400 = n (\frac{2 ( - 5 ) + 4 ( n - 1 )}{2})

- 5 x^{2} + x + 1 = 0

0.12 \cdot 1 0^{- 5} x^{2} + 0.026 x + 100 = 0

What are the solutions to the equation 9y^2-y=0 ?
The solutions to the equation 9y^2-y=0 are y= 1/9 ,y=0
Find the zeros of 9y^2-y=0
The zeros of 9y^2-y=0 are y= 1/9 ,y=0