What are the solutions to the equation x^2-4x-26=-2 ?

The solutions to the equation x^2-4x-26=-2 are x=2(1+sqrt(7)),x=2(1-sqrt(7))

Find the zeros of x^2-4x-26=-2

The zeros of x^2-4x-26=-2 are x=2(1+sqrt(7)),x=2(1-sqrt(7))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 4 x - 26 = - 2

x = 2 (1 + 7), x = 2 (1 - 7)

Decimal Notation

x = 7.29150 \dots, x = - 3.29150 \dots

Solution steps

x^{2} - 4 x - 26 = - 2

Move

2

to the left side

x^{2} - 4 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 24) = 47

x_{1, 2} = \frac{- ( - 4 ) \pm 4 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 7}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 4 7}{2 \cdot 1}

x = \frac{- ( - 4 ) + 4 7}{2 \cdot 1} : 2 (1 + 7)

x = \frac{- ( - 4 ) - 4 7}{2 \cdot 1} : 2 (1 - 7)

The solutions to the quadratic equation are:

x = 2 (1 + 7), x = 2 (1 - 7)

400 = n (\frac{2 ( - 5 ) + 4 ( n - 1 )}{2})

- 5 x^{2} + x + 1 = 0

0.12 \cdot 1 0^{- 5} x^{2} + 0.026 x + 100 = 0

(x + \frac{b}{3})^{2} - 2 - \frac{b ^{2}}{9} = 0

2 x^{2} - x - 2

What are the solutions to the equation x^2-4x-26=-2 ?
The solutions to the equation x^2-4x-26=-2 are x=2(1+sqrt(7)),x=2(1-sqrt(7))
Find the zeros of x^2-4x-26=-2
The zeros of x^2-4x-26=-2 are x=2(1+sqrt(7)),x=2(1-sqrt(7))