What are the solutions to the equation -2p^2+3p+6=0 ?

The solutions to the equation -2p^2+3p+6=0 are p=-(-3+sqrt(57))/4 ,p=(3+sqrt(57))/4

Find the zeros of -2p^2+3p+6=0

The zeros of -2p^2+3p+6=0 are p=-(-3+sqrt(57))/4 ,p=(3+sqrt(57))/4

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- 2 p^{2} + 3 p + 6 = 0

p = - \frac{- 3 + 57}{4}, p = \frac{3 + 57}{4}

Decimal Notation

p = - 1.13745 \dots, p = 2.63745 \dots

Solution steps

- 2 p^{2} + 3 p + 6 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 2 ) \cdot 6}{2 ( - 2 )}

3^{2} - 4 (- 2) \cdot 6 = 57

p_{1, 2} = \frac{- 3 \pm 57}{2 ( - 2 )}

Separate the solutions

p_{1} = \frac{- 3 + 57}{2 ( - 2 )}, p_{2} = \frac{- 3 - 57}{2 ( - 2 )}

p = \frac{- 3 + 57}{2 ( - 2 )} : - \frac{- 3 + 57}{4}

p = \frac{- 3 - 57}{2 ( - 2 )} : \frac{3 + 57}{4}

The solutions to the quadratic equation are:

p = - \frac{- 3 + 57}{4}, p = \frac{3 + 57}{4}

- 9 x^{2} + x - 8 = 0

(x - 21)^{2} = 484

X^{3} = (X - 300)^{3} + 100

b^{2} - b - 12 = 0

- n (5 n - 4) = 0

What are the solutions to the equation -2p^2+3p+6=0 ?
The solutions to the equation -2p^2+3p+6=0 are p=-(-3+sqrt(57))/4 ,p=(3+sqrt(57))/4
Find the zeros of -2p^2+3p+6=0
The zeros of -2p^2+3p+6=0 are p=-(-3+sqrt(57))/4 ,p=(3+sqrt(57))/4