What are the solutions to the equation -9x^2+x-8=0 ?

The solutions to the equation -9x^2+x-8=0 are x= 1/18-i(sqrt(287))/(18),x= 1/18+i(sqrt(287))/(18)

Find the zeros of -9x^2+x-8=0

The zeros of -9x^2+x-8=0 are x= 1/18-i(sqrt(287))/(18),x= 1/18+i(sqrt(287))/(18)

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- 9 x^{2} + x - 8 = 0

x = \frac{1}{18} - i \frac{287}{18}, x = \frac{1}{18} + i \frac{287}{18}

Solution steps

- 9 x^{2} + x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 9 ) ( - 8 )}{2 ( - 9 )}

Simplify

1^{2} - 4 (- 9) (- 8) : 287 i

x_{1, 2} = \frac{- 1 \pm 287 i}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- 1 + 287 i}{2 ( - 9 )}, x_{2} = \frac{- 1 - 287 i}{2 ( - 9 )}

x = \frac{- 1 + 287 i}{2 ( - 9 )} : \frac{1}{18} - i \frac{287}{18}

x = \frac{- 1 - 287 i}{2 ( - 9 )} : \frac{1}{18} + i \frac{287}{18}

The solutions to the quadratic equation are:

x = \frac{1}{18} - i \frac{287}{18}, x = \frac{1}{18} + i \frac{287}{18}

(x - 21)^{2} = 484

X^{3} = (X - 300)^{3} + 100

b^{2} - b - 12 = 0

- n (5 n - 4) = 0

b, 4^{2} + b^{2} = c^{2}

What are the solutions to the equation -9x^2+x-8=0 ?
The solutions to the equation -9x^2+x-8=0 are x= 1/18-i(sqrt(287))/(18),x= 1/18+i(sqrt(287))/(18)
Find the zeros of -9x^2+x-8=0
The zeros of -9x^2+x-8=0 are x= 1/18-i(sqrt(287))/(18),x= 1/18+i(sqrt(287))/(18)