What are the solutions to the equation solvefor b,4^2+b^2=c^2 ?

The solutions to the equation solvefor b,4^2+b^2=c^2 are b=sqrt(c^2-16),b=-sqrt(c^2-16)

Find the zeros of solvefor b,4^2+b^2=c^2

The zeros of solvefor b,4^2+b^2=c^2 are b=sqrt(c^2-16),b=-sqrt(c^2-16)

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solve for

b, 4^{2} + b^{2} = c^{2}

b = c^{2} - 16, b = - c^{2} - 16

Solution steps

4^{2} + b^{2} = c^{2}

Move

4^{2}

to the right side

b^{2} = c^{2} - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = c^{2} - 16, b = - c^{2} - 16

x^{2} - 7 \cdot + 6 = 0

1.5 = (\frac{4}{81}) (x - 3)^{2} + 1

3 x^{2} + 2 x - 1 = 2

1 5^{2} = x^{2} + 7. 5^{2}

p, 10 - p^{2} = 3 p

What are the solutions to the equation solvefor b,4^2+b^2=c^2 ?
The solutions to the equation solvefor b,4^2+b^2=c^2 are b=sqrt(c^2-16),b=-sqrt(c^2-16)
Find the zeros of solvefor b,4^2+b^2=c^2
The zeros of solvefor b,4^2+b^2=c^2 are b=sqrt(c^2-16),b=-sqrt(c^2-16)