What are the solutions to the equation 3x^2+2x-1=2 ?

The solutions to the equation 3x^2+2x-1=2 are x=(-1+sqrt(10))/3 ,x=-(1+sqrt(10))/3

Find the zeros of 3x^2+2x-1=2

The zeros of 3x^2+2x-1=2 are x=(-1+sqrt(10))/3 ,x=-(1+sqrt(10))/3

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3 x^{2} + 2 x - 1 = 2

x = \frac{- 1 + 10}{3}, x = - \frac{1 + 10}{3}

Decimal Notation

x = 0.72075 \dots, x = - 1.38742 \dots

Solution steps

3 x^{2} + 2 x - 1 = 2

Move

2

to the left side

3 x^{2} + 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 3 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 3) = 210

x_{1, 2} = \frac{- 2 \pm 2 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 2 10}{2 \cdot 3}, x_{2} = \frac{- 2 - 2 10}{2 \cdot 3}

x = \frac{- 2 + 2 10}{2 \cdot 3} : \frac{- 1 + 10}{3}

x = \frac{- 2 - 2 10}{2 \cdot 3} : - \frac{1 + 10}{3}

The solutions to the quadratic equation are:

x = \frac{- 1 + 10}{3}, x = - \frac{1 + 10}{3}

1 5^{2} = x^{2} + 7. 5^{2}

p, 10 - p^{2} = 3 p

X^{2} - 2 X = - X + 6

- 5 x^{2} - 40 x - 86

- 3 x^{2} - 2 x = - 10

What are the solutions to the equation 3x^2+2x-1=2 ?
The solutions to the equation 3x^2+2x-1=2 are x=(-1+sqrt(10))/3 ,x=-(1+sqrt(10))/3
Find the zeros of 3x^2+2x-1=2
The zeros of 3x^2+2x-1=2 are x=(-1+sqrt(10))/3 ,x=-(1+sqrt(10))/3