What are the solutions to the equation -3x^2-2x=-10 ?

The solutions to the equation -3x^2-2x=-10 are x=-(1+sqrt(31))/3 ,x=(sqrt(31)-1)/3

Find the zeros of -3x^2-2x=-10

The zeros of -3x^2-2x=-10 are x=-(1+sqrt(31))/3 ,x=(sqrt(31)-1)/3

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- 3 x^{2} - 2 x = - 10

x = - \frac{1 + 31}{3}, x = \frac{31 - 1}{3}

Decimal Notation

x = - 2.18925 \dots, x = 1.52258 \dots

Solution steps

- 3 x^{2} - 2 x = - 10

Move

10

to the left side

- 3 x^{2} - 2 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 3 ) \cdot 10}{2 ( - 3 )}

(- 2)^{2} - 4 (- 3) \cdot 10 = 231

x_{1, 2} = \frac{- ( - 2 ) \pm 2 31}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 31}{2 ( - 3 )}, x_{2} = \frac{- ( - 2 ) - 2 31}{2 ( - 3 )}

x = \frac{- ( - 2 ) + 2 31}{2 ( - 3 )} : - \frac{1 + 31}{3}

x = \frac{- ( - 2 ) - 2 31}{2 ( - 3 )} : \frac{31 - 1}{3}

The solutions to the quadratic equation are:

x = - \frac{1 + 31}{3}, x = \frac{31 - 1}{3}

x^{2} + 2^{2} = 0

3 q^{2} - 18 q + 24 = 0

0 = 1 - 0^{2} - z^{2}

5 x^{2} - 7 x = - 4 + 3 x^{2}

- 11 a^{2} + 32 a + 256 = 0

What are the solutions to the equation -3x^2-2x=-10 ?
The solutions to the equation -3x^2-2x=-10 are x=-(1+sqrt(31))/3 ,x=(sqrt(31)-1)/3
Find the zeros of -3x^2-2x=-10
The zeros of -3x^2-2x=-10 are x=-(1+sqrt(31))/3 ,x=(sqrt(31)-1)/3