What are the solutions to the equation 2pir=pir^2 ?

The solutions to the equation 2pir=pir^2 are r=0,r=2

Find the zeros of 2pir=pir^2

The zeros of 2pir=pir^2 are r=0,r=2

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2 π r = π r^{2}

r = 0, r = 2

Solution steps

2 π r = π r^{2}

Move

π r^{2}

to the left side

2 π r - π r^{2} = 0

Factor

2 π r - π r^{2} : - π r (r - 2)

- π r (r - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r = 0 or r - 2 = 0

Solve

r - 2 = 0 : r = 2

The solutions to the quadratic equation are:

r = 0, r = 2

1 8^{2} + 1 8^{2} = x^{2}

y, 2 x^{3} - 4 x - 4 y^{2} = 0

x^{2} + 5 x + 1 = \frac{3}{2}

x, 9 x^{2} - 12 x + 4 = 0

r^{2} = (y - 2)^{2} + (\frac{x}{2})^{2}, y

What are the solutions to the equation 2pir=pir^2 ?
The solutions to the equation 2pir=pir^2 are r=0,r=2
Find the zeros of 2pir=pir^2
The zeros of 2pir=pir^2 are r=0,r=2