What are the solutions to the equation solvefor x,9x^2-12x+4=0 ?

The solutions to the equation solvefor x,9x^2-12x+4=0 are x= 2/3

Find the zeros of solvefor x,9x^2-12x+4=0

The zeros of solvefor x,9x^2-12x+4=0 are x= 2/3

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x, 9 x^{2} - 12 x + 4 = 0

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

9 x^{2} - 12 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

(- 12)^{2} - 4 \cdot 9 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 9}

x = \frac{- ( - 12 )}{2 \cdot 9}

\frac{- ( - 12 )}{2 \cdot 9} = \frac{2}{3}

x = \frac{2}{3}

The solution to the quadratic equation is:

x = \frac{2}{3}

r^{2} = (y - 2)^{2} + (\frac{x}{2})^{2}, y

(x + 3)^{2} + 6 (x + 3) = 16

5 x + x^{2} = 84

(4 x^{2} - 5 x + 13) + (- 11 x^{2} + 5 x + 4) = a x^{2} + 17

1 - x - 6 x^{2} = 0

What are the solutions to the equation solvefor x,9x^2-12x+4=0 ?
The solutions to the equation solvefor x,9x^2-12x+4=0 are x= 2/3
Find the zeros of solvefor x,9x^2-12x+4=0
The zeros of solvefor x,9x^2-12x+4=0 are x= 2/3