What are the solutions to the equation 1-x-6x^2=0 ?

The solutions to the equation 1-x-6x^2=0 are x=-1/2 ,x= 1/3

Find the zeros of 1-x-6x^2=0

The zeros of 1-x-6x^2=0 are x=-1/2 ,x= 1/3

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1 - x - 6 x^{2} = 0

x = - \frac{1}{2}, x = \frac{1}{3}

Decimal Notation

x = - 0.5, x = 0.33333 \dots

Solution steps

1 - x - 6 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 6 x^{2} - x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 6 ) \cdot 1}{2 ( - 6 )}

(- 1)^{2} - 4 (- 6) \cdot 1 = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 ( - 6 )}, x_{2} = \frac{- ( - 1 ) - 5}{2 ( - 6 )}

x = \frac{- ( - 1 ) + 5}{2 ( - 6 )} : - \frac{1}{2}

x = \frac{- ( - 1 ) - 5}{2 ( - 6 )} : \frac{1}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = \frac{1}{3}

2 (x - \frac{m}{2}) (x - (m - 1)) = 0

x, z = 3 x^{2} - 2 x y + y

4 x^{2} - 6 x + 21 = 15

x, f^{- 1} (x) = x^{2} - 2 x + 1

(x) = 5 x^{2} - 40 x - 40

What are the solutions to the equation 1-x-6x^2=0 ?
The solutions to the equation 1-x-6x^2=0 are x=-1/2 ,x= 1/3
Find the zeros of 1-x-6x^2=0
The zeros of 1-x-6x^2=0 are x=-1/2 ,x= 1/3