What are the solutions to the equation (x)=5x^2-40x-40 ?

The solutions to the equation (x)=5x^2-40x-40 are x=(41+sqrt(2481))/(10),x=(41-sqrt(2481))/(10)

Find the zeros of (x)=5x^2-40x-40

The zeros of (x)=5x^2-40x-40 are x=(41+sqrt(2481))/(10),x=(41-sqrt(2481))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x) = 5 x^{2} - 40 x - 40

x = \frac{41 + 2481}{10}, x = \frac{41 - 2481}{10}

Decimal Notation

x = 9.08096 \dots, x = - 0.88096 \dots

Solution steps

(x) = 5 x^{2} - 40 x - 40

Refine

x = 5 x^{2} - 40 x - 40

Switch sides

5 x^{2} - 40 x - 40 = x

Move

x

to the left side

5 x^{2} - 41 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 41 ) \pm ( - 41 ) ^{2} - 4 \cdot 5 ( - 40 )}{2 \cdot 5}

(- 41)^{2} - 4 \cdot 5 (- 40) = 2481

x_{1, 2} = \frac{- ( - 41 ) \pm 2481}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 41 ) + 2481}{2 \cdot 5}, x_{2} = \frac{- ( - 41 ) - 2481}{2 \cdot 5}

x = \frac{- ( - 41 ) + 2481}{2 \cdot 5} : \frac{41 + 2481}{10}

x = \frac{- ( - 41 ) - 2481}{2 \cdot 5} : \frac{41 - 2481}{10}

The solutions to the quadratic equation are:

x = \frac{41 + 2481}{10}, x = \frac{41 - 2481}{10}

(3 x + 1) (x - 4) = 0

0 = - 4.9 (t - 0.5)^{2} + 7

m^{1} = m^{2}

x, 18 x^{2} y + 4 y^{3} - 2 = 0

- 2 x^{2} + 4 x + 9 = - 3

What are the solutions to the equation (x)=5x^2-40x-40 ?
The solutions to the equation (x)=5x^2-40x-40 are x=(41+sqrt(2481))/(10),x=(41-sqrt(2481))/(10)
Find the zeros of (x)=5x^2-40x-40
The zeros of (x)=5x^2-40x-40 are x=(41+sqrt(2481))/(10),x=(41-sqrt(2481))/(10)