What are the solutions to the equation y^2+50y+336=0 ?

The solutions to the equation y^2+50y+336=0 are y=-8,y=-42

Find the zeros of y^2+50y+336=0

The zeros of y^2+50y+336=0 are y=-8,y=-42

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y^{2} + 50 y + 336 = 0

y = - 8, y = - 42

Solution steps

y^{2} + 50 y + 336 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 1 \cdot 336}{2 \cdot 1}

5 0^{2} - 4 \cdot 1 \cdot 336 = 34

y_{1, 2} = \frac{- 50 \pm 34}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 50 + 34}{2 \cdot 1}, y_{2} = \frac{- 50 - 34}{2 \cdot 1}

y = \frac{- 50 + 34}{2 \cdot 1} : - 8

y = \frac{- 50 - 34}{2 \cdot 1} : - 42

The solutions to the quadratic equation are:

y = - 8, y = - 42

6 x - 1 \cdot 6 x \cdot 6 x + 2 = 7776

7 + 4 x - x^{2} = 0

2 x^{2} = 28 - x

8 f^{2} + 8 f + 2 = 0

4 x^{2} - 30 x + 72 = 0

What are the solutions to the equation y^2+50y+336=0 ?
The solutions to the equation y^2+50y+336=0 are y=-8,y=-42
Find the zeros of y^2+50y+336=0
The zeros of y^2+50y+336=0 are y=-8,y=-42